5(2r+4)=10(r-2)

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Solution for 5(2r+4)=10(r-2) equation: 



5(2r+4)=10(r-2)

We move all terms to the left:

5(2r+4)-(10(r-2))=0

We multiply parentheses

10r-(10(r-2))+20=0



We calculate terms in parentheses: -(10(r-2)), so:

10(r-2)

We multiply parentheses

10r-20

Back to the equation:

-(10r-20)



We get rid of parentheses

10r-10r+20+20=0

We add all the numbers together, and all the variables

40!=0

There is no solution for this equation

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