5(2n+5)=9(9n+3)2

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Solution for 5(2n+5)=9(9n+3)2 equation: 



5(2n+5)=9(9n+3)2

We move all terms to the left:

5(2n+5)-(9(9n+3)2)=0

We multiply parentheses

10n-(9(9n+3)2)+25=0



We calculate terms in parentheses: -(9(9n+3)2), so:

9(9n+3)2

We multiply parentheses

162n+54

Back to the equation:

-(162n+54)



We get rid of parentheses

10n-162n-54+25=0

We add all the numbers together, and all the variables

-152n-29=0

We move all terms containing n to the left, all other terms to the right

-152n=29

n=29/-152

n=-29/152

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