5(2m+3)-(1-2m)=2(9+6m-3-m)

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Solution for 5(2m+3)-(1-2m)=2(9+6m-3-m) equation: 



5(2m+3)-(1-2m)=2(9+6m-3-m)

We move all terms to the left:

5(2m+3)-(1-2m)-(2(9+6m-3-m))=0

We add all the numbers together, and all the variables

5(2m+3)-(-2m+1)-(2(5m+6))=0

We multiply parentheses

10m-(-2m+1)-(2(5m+6))+15=0

We get rid of parentheses

10m+2m-(2(5m+6))-1+15=0



We calculate terms in parentheses: -(2(5m+6)), so:

2(5m+6)

We multiply parentheses

10m+12

Back to the equation:

-(10m+12)



We add all the numbers together, and all the variables

12m-(10m+12)+14=0

We get rid of parentheses

12m-10m-12+14=0

We add all the numbers together, and all the variables

2m+2=0

We move all terms containing m to the left, all other terms to the right

2m=-2

m=-2/2

m=-1

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