5(2k+3)-2(k-8)=3(2k+4)+k-3

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Solution for 5(2k+3)-2(k-8)=3(2k+4)+k-3 equation: 



5(2k+3)-2(k-8)=3(2k+4)+k-3

We move all terms to the left:

5(2k+3)-2(k-8)-(3(2k+4)+k-3)=0

We multiply parentheses

10k-2k-(3(2k+4)+k-3)+15+16=0



We calculate terms in parentheses: -(3(2k+4)+k-3), so:

3(2k+4)+k-3

We add all the numbers together, and all the variables

k+3(2k+4)-3

We multiply parentheses

k+6k+12-3

We add all the numbers together, and all the variables

7k+9

Back to the equation:

-(7k+9)



We add all the numbers together, and all the variables

8k-(7k+9)+31=0

We get rid of parentheses

8k-7k-9+31=0

We add all the numbers together, and all the variables

k+22=0

We move all terms containing k to the left, all other terms to the right

k=-22

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