10x-(2x+1)=-3(15-4x)

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Solution for 10x-(2x+1)=-3(15-4x) equation: 



10x-(2x+1)=-3(15-4x)

We move all terms to the left:

10x-(2x+1)-(-3(15-4x))=0

We add all the numbers together, and all the variables

10x-(2x+1)-(-3(-4x+15))=0

We get rid of parentheses

10x-2x-(-3(-4x+15))-1=0



We calculate terms in parentheses: -(-3(-4x+15)), so:

-3(-4x+15)

We multiply parentheses

12x-45

Back to the equation:

-(12x-45)



We add all the numbers together, and all the variables

8x-(12x-45)-1=0

We get rid of parentheses

8x-12x+45-1=0

We add all the numbers together, and all the variables

-4x+44=0

We move all terms containing x to the left, all other terms to the right

-4x=-44

x=-44/-4

x=+11

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