5(2c-3)=(3c-5)

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Solution for 5(2c-3)=(3c-5) equation: 



5(2c-3)=(3c-5)

We move all terms to the left:

5(2c-3)-((3c-5))=0

We multiply parentheses

10c-((3c-5))-15=0



We calculate terms in parentheses: -((3c-5)), so:

(3c-5)

We get rid of parentheses

3c-5

Back to the equation:

-(3c-5)



We get rid of parentheses

10c-3c+5-15=0

We add all the numbers together, and all the variables

7c-10=0

We move all terms containing c to the left, all other terms to the right

7c=10

c=10/7

c=1+3/7

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