6(3x-2)=3(x+1)

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Solution for 6(3x-2)=3(x+1) equation: 



6(3x-2)=3(x+1)

We move all terms to the left:

6(3x-2)-(3(x+1))=0

We multiply parentheses

18x-(3(x+1))-12=0



We calculate terms in parentheses: -(3(x+1)), so:

3(x+1)

We multiply parentheses

3x+3

Back to the equation:

-(3x+3)



We get rid of parentheses

18x-3x-3-12=0

We add all the numbers together, and all the variables

15x-15=0

We move all terms containing x to the left, all other terms to the right

15x=15

x=15/15

x=1

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