5(2b-4)-8=-8+7(-5+b)

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Solution for 5(2b-4)-8=-8+7(-5+b) equation: 



5(2b-4)-8=-8+7(-5+b)

We move all terms to the left:

5(2b-4)-8-(-8+7(-5+b))=0

We add all the numbers together, and all the variables

5(2b-4)-(-8+7(b-5))-8=0

We multiply parentheses

10b-(-8+7(b-5))-20-8=0



We calculate terms in parentheses: -(-8+7(b-5)), so:

-8+7(b-5)

determiningTheFunctionDomain
7(b-5)-8

We multiply parentheses

7b-35-8

We add all the numbers together, and all the variables

7b-43

Back to the equation:

-(7b-43)



We add all the numbers together, and all the variables

10b-(7b-43)-28=0

We get rid of parentheses

10b-7b+43-28=0

We add all the numbers together, and all the variables

3b+15=0

We move all terms containing b to the left, all other terms to the right

3b=-15

b=-15/3

b=-5

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