6x2+3x-5=0

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Solution for 6x2+3x-5=0 equation: 



6x^2+3x-5=0

a = 6; b = 3; c = -5;
Δ = b2-4ac
Δ = 32-4·6·(-5)
Δ = 129
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{129}}{2*6}=\frac{-3-\sqrt{129}}{12}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{129}}{2*6}=\frac{-3+\sqrt{129}}{12}
$

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