5(2a-3)=4(a+3)-3(1+2a)

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Solution for 5(2a-3)=4(a+3)-3(1+2a) equation: 



5(2a-3)=4(a+3)-3(1+2a)

We move all terms to the left:

5(2a-3)-(4(a+3)-3(1+2a))=0

We add all the numbers together, and all the variables

5(2a-3)-(4(a+3)-3(2a+1))=0

We multiply parentheses

10a-(4(a+3)-3(2a+1))-15=0



We calculate terms in parentheses: -(4(a+3)-3(2a+1)), so:

4(a+3)-3(2a+1)

We multiply parentheses

4a-6a+12-3

We add all the numbers together, and all the variables

-2a+9

Back to the equation:

-(-2a+9)



We get rid of parentheses

10a+2a-9-15=0

We add all the numbers together, and all the variables

12a-24=0

We move all terms containing a to the left, all other terms to the right

12a=24

a=24/12

a=2

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