2(6c+1)-17=9c+3

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Solution for 2(6c+1)-17=9c+3 equation: 



2(6c+1)-17=9c+3

We move all terms to the left:

2(6c+1)-17-(9c+3)=0

We multiply parentheses

12c-(9c+3)+2-17=0

We get rid of parentheses

12c-9c-3+2-17=0

We add all the numbers together, and all the variables

3c-18=0

We move all terms containing c to the left, all other terms to the right

3c=18

c=18/3

c=6

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