5(2a-1)=-10(a-5)+5

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Solution for 5(2a-1)=-10(a-5)+5 equation: 



5(2a-1)=-10(a-5)+5

We move all terms to the left:

5(2a-1)-(-10(a-5)+5)=0

We multiply parentheses

10a-(-10(a-5)+5)-5=0



We calculate terms in parentheses: -(-10(a-5)+5), so:

-10(a-5)+5

We multiply parentheses

-10a+50+5

We add all the numbers together, and all the variables

-10a+55

Back to the equation:

-(-10a+55)



We get rid of parentheses

10a+10a-55-5=0

We add all the numbers together, and all the variables

20a-60=0

We move all terms containing a to the left, all other terms to the right

20a=60

a=60/20

a=3

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