4(c+12)=6c+18

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Solution for 4(c+12)=6c+18 equation: 



4(c+12)=6c+18

We move all terms to the left:

4(c+12)-(6c+18)=0

We multiply parentheses

4c-(6c+18)+48=0

We get rid of parentheses

4c-6c-18+48=0

We add all the numbers together, and all the variables

-2c+30=0

We move all terms containing c to the left, all other terms to the right

-2c=-30

c=-30/-2

c=+15

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