5(2a-1)=-10(a-5)

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Solution for 5(2a-1)=-10(a-5) equation: 



5(2a-1)=-10(a-5)

We move all terms to the left:

5(2a-1)-(-10(a-5))=0

We multiply parentheses

10a-(-10(a-5))-5=0



We calculate terms in parentheses: -(-10(a-5)), so:

-10(a-5)

We multiply parentheses

-10a+50

Back to the equation:

-(-10a+50)



We get rid of parentheses

10a+10a-50-5=0

We add all the numbers together, and all the variables

20a-55=0

We move all terms containing a to the left, all other terms to the right

20a=55

a=55/20

a=2+3/4

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