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5(2/5x=1)=(13/5)5
We move all terms to the left:
5(2/5x-(1))=0
Domain of the equation: 5x-1)!=0We multiply parentheses
x∈R
10x-5=0
We move all terms containing x to the left, all other terms to the right
10x=5
x=5/10
x=1/2
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