(5x+3)+(20x+7)=(40x-35)

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Solution for (5x+3)+(20x+7)=(40x-35) equation: 



(5x+3)+(20x+7)=(40x-35)

We move all terms to the left:

(5x+3)+(20x+7)-((40x-35))=0

We get rid of parentheses

5x+20x-((40x-35))+3+7=0



We calculate terms in parentheses: -((40x-35)), so:

(40x-35)

We get rid of parentheses

40x-35

Back to the equation:

-(40x-35)



We add all the numbers together, and all the variables

25x-(40x-35)+10=0

We get rid of parentheses

25x-40x+35+10=0

We add all the numbers together, and all the variables

-15x+45=0

We move all terms containing x to the left, all other terms to the right

-15x=-45

x=-45/-15

x=+3

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