-4(-8y+4)-7y=7(y-3)-9

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Solution for -4(-8y+4)-7y=7(y-3)-9 equation: 



-4(-8y+4)-7y=7(y-3)-9

We move all terms to the left:

-4(-8y+4)-7y-(7(y-3)-9)=0

We add all the numbers together, and all the variables

-7y-4(-8y+4)-(7(y-3)-9)=0

We multiply parentheses

-7y+32y-(7(y-3)-9)-16=0



We calculate terms in parentheses: -(7(y-3)-9), so:

7(y-3)-9

We multiply parentheses

7y-21-9

We add all the numbers together, and all the variables

7y-30

Back to the equation:

-(7y-30)



We add all the numbers together, and all the variables

25y-(7y-30)-16=0

We get rid of parentheses

25y-7y+30-16=0

We add all the numbers together, and all the variables

18y+14=0

We move all terms containing y to the left, all other terms to the right

18y=-14

y=-14/18

y=-7/9

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