6(2b-1)+3b=3(5b-2)

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Solution for 6(2b-1)+3b=3(5b-2) equation: 



6(2b-1)+3b=3(5b-2)

We move all terms to the left:

6(2b-1)+3b-(3(5b-2))=0

We add all the numbers together, and all the variables

3b+6(2b-1)-(3(5b-2))=0

We multiply parentheses

3b+12b-(3(5b-2))-6=0



We calculate terms in parentheses: -(3(5b-2)), so:

3(5b-2)

We multiply parentheses

15b-6

Back to the equation:

-(15b-6)



We add all the numbers together, and all the variables

15b-(15b-6)-6=0

We get rid of parentheses

15b-15b+6-6=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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