5(2-v)-5v=-2(v+3)

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Solution for 5(2-v)-5v=-2(v+3) equation: 



5(2-v)-5v=-2(v+3)

We move all terms to the left:

5(2-v)-5v-(-2(v+3))=0

We add all the numbers together, and all the variables

5(-1v+2)-5v-(-2(v+3))=0

We add all the numbers together, and all the variables

-5v+5(-1v+2)-(-2(v+3))=0

We multiply parentheses

-5v-5v-(-2(v+3))+10=0



We calculate terms in parentheses: -(-2(v+3)), so:

-2(v+3)

We multiply parentheses

-2v-6

Back to the equation:

-(-2v-6)



We add all the numbers together, and all the variables

-10v-(-2v-6)+10=0

We get rid of parentheses

-10v+2v+6+10=0

We add all the numbers together, and all the variables

-8v+16=0

We move all terms containing v to the left, all other terms to the right

-8v=-16

v=-16/-8

v=+2

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