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z+2/z=-6
We move all terms to the left:
z+2/z-(-6)=0
Domain of the equation: z!=0We add all the numbers together, and all the variables
z∈R
z+2/z+6=0
We multiply all the terms by the denominator
z*z+6*z+2=0
We add all the numbers together, and all the variables
6z+z*z+2=0
Wy multiply elements
z^2+6z+2=0
a = 1; b = 6; c = +2;
Δ = b2-4ac
Δ = 62-4·1·2
Δ = 28
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{28}=\sqrt{4*7}=\sqrt{4}*\sqrt{7}=2\sqrt{7}$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{7}}{2*1}=\frac{-6-2\sqrt{7}}{2} $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{7}}{2*1}=\frac{-6+2\sqrt{7}}{2} $
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