5(2+v)-v=4+2(v+1)

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Solution for 5(2+v)-v=4+2(v+1) equation: 



5(2+v)-v=4+2(v+1)

We move all terms to the left:

5(2+v)-v-(4+2(v+1))=0

We add all the numbers together, and all the variables

5(v+2)-v-(4+2(v+1))=0

We add all the numbers together, and all the variables

-1v+5(v+2)-(4+2(v+1))=0

We multiply parentheses

-1v+5v-(4+2(v+1))+10=0



We calculate terms in parentheses: -(4+2(v+1)), so:

4+2(v+1)

determiningTheFunctionDomain
2(v+1)+4

We multiply parentheses

2v+2+4

We add all the numbers together, and all the variables

2v+6

Back to the equation:

-(2v+6)



We add all the numbers together, and all the variables

4v-(2v+6)+10=0

We get rid of parentheses

4v-2v-6+10=0

We add all the numbers together, and all the variables

2v+4=0

We move all terms containing v to the left, all other terms to the right

2v=-4

v=-4/2

v=-2

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