4(x-2)+2x=3(x+4)-11

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Solution for 4(x-2)+2x=3(x+4)-11 equation: 



4(x-2)+2x=3(x+4)-11

We move all terms to the left:

4(x-2)+2x-(3(x+4)-11)=0

We add all the numbers together, and all the variables

2x+4(x-2)-(3(x+4)-11)=0

We multiply parentheses

2x+4x-(3(x+4)-11)-8=0



We calculate terms in parentheses: -(3(x+4)-11), so:

3(x+4)-11

We multiply parentheses

3x+12-11

We add all the numbers together, and all the variables

3x+1

Back to the equation:

-(3x+1)



We add all the numbers together, and all the variables

6x-(3x+1)-8=0

We get rid of parentheses

6x-3x-1-8=0

We add all the numbers together, and all the variables

3x-9=0

We move all terms containing x to the left, all other terms to the right

3x=9

x=9/3

x=3

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