5(2+v)-v=10+4(v+4)

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Solution for 5(2+v)-v=10+4(v+4) equation: 



5(2+v)-v=10+4(v+4)

We move all terms to the left:

5(2+v)-v-(10+4(v+4))=0

We add all the numbers together, and all the variables

5(v+2)-v-(10+4(v+4))=0

We add all the numbers together, and all the variables

-1v+5(v+2)-(10+4(v+4))=0

We multiply parentheses

-1v+5v-(10+4(v+4))+10=0



We calculate terms in parentheses: -(10+4(v+4)), so:

10+4(v+4)

determiningTheFunctionDomain
4(v+4)+10

We multiply parentheses

4v+16+10

We add all the numbers together, and all the variables

4v+26

Back to the equation:

-(4v+26)



We add all the numbers together, and all the variables

4v-(4v+26)+10=0

We get rid of parentheses

4v-4v-26+10=0

We add all the numbers together, and all the variables

-16!=0

There is no solution for this equation

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