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x(3x+10)+2(4x+15)=1080
We move all terms to the left:
x(3x+10)+2(4x+15)-(1080)=0
We multiply parentheses
3x^2+10x+8x+30-1080=0
We add all the numbers together, and all the variables
3x^2+18x-1050=0
a = 3; b = 18; c = -1050;
Δ = b2-4ac
Δ = 182-4·3·(-1050)
Δ = 12924
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12924}=\sqrt{36*359}=\sqrt{36}*\sqrt{359}=6\sqrt{359}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-6\sqrt{359}}{2*3}=\frac{-18-6\sqrt{359}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+6\sqrt{359}}{2*3}=\frac{-18+6\sqrt{359}}{6} $
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