5(2+n)=10(n-2)

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Solution for 5(2+n)=10(n-2) equation: 



5(2+n)=10(n-2)

We move all terms to the left:

5(2+n)-(10(n-2))=0

We add all the numbers together, and all the variables

5(n+2)-(10(n-2))=0

We multiply parentheses

5n-(10(n-2))+10=0



We calculate terms in parentheses: -(10(n-2)), so:

10(n-2)

We multiply parentheses

10n-20

Back to the equation:

-(10n-20)



We get rid of parentheses

5n-10n+20+10=0

We add all the numbers together, and all the variables

-5n+30=0

We move all terms containing n to the left, all other terms to the right

-5n=-30

n=-30/-5

n=+6

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