1=-2(-3)+b,b

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Solution for 1=-2(-3)+b,b equation:



1=-2(-3)+b.b
We move all terms to the left:
1-(-2(-3)+b.b)=0
We calculate terms in parentheses: -(-2(-3)+b.b), so:
-2(-3)+b.b
determiningTheFunctionDomain b.b-2(-3)
We add all the numbers together, and all the variables
b.b+6
Back to the equation:
-(b.b+6)
We get rid of parentheses
-b.b-6+1=0
We add all the numbers together, and all the variables
-b.b-5=0
We move all terms containing b to the left, all other terms to the right
-b.b=5
b=5/1
b=5

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