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5(1/5+c)=3+1/2
We move all terms to the left:
5(1/5+c)-(3+1/2)=0
Domain of the equation: 5+c)!=0We add all the numbers together, and all the variables
We move all terms containing c to the left, all other terms to the right
c)!=-5
c!=-5/1
c!=-5
c∈R
5(+c+1/5)-(1/2+3)=0
We multiply parentheses
5c+1/5*5-(1/2+3)=0
We get rid of parentheses
5c-3+1/5*5-1/2=0
We calculate fractions
There is no solution for this equation
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