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(2x-3)/13x-3=1/5
We move all terms to the left:
(2x-3)/13x-3-(1/5)=0
Domain of the equation: 13x!=0We add all the numbers together, and all the variables
x!=0/13
x!=0
x∈R
(2x-3)/13x-3-(+1/5)=0
We get rid of parentheses
(2x-3)/13x-3-1/5=0
We calculate fractions
(10x-15)/65x+(-13x)/65x-3=0
We multiply all the terms by the denominator
(10x-15)+(-13x)-3*65x=0
Wy multiply elements
(10x-15)+(-13x)-195x=0
We get rid of parentheses
10x-13x-195x-15=0
We add all the numbers together, and all the variables
-198x-15=0
We move all terms containing x to the left, all other terms to the right
-198x=15
x=15/-198
x=-5/66
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