5(1/3b+3)=6(b+9)

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Solution for 5(1/3b+3)=6(b+9) equation: 



5(1/3b+3)=6(b+9)

We move all terms to the left:

5(1/3b+3)-(6(b+9))=0



Domain of the equation: 3b+3)!=0

b∈R



We multiply parentheses

5b-(6(b+9))+15=0



We calculate terms in parentheses: -(6(b+9)), so:

6(b+9)

We multiply parentheses

6b+54

Back to the equation:

-(6b+54)



We get rid of parentheses

5b-6b-54+15=0

We add all the numbers together, and all the variables

-1b-39=0

We move all terms containing b to the left, all other terms to the right

-b=39

b=39/-1

b=-39

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