-4(d+1)+2(d-2=10/3

Solution for -4(d+1)+2(d-2=10/3 equation:

-4(d+1)+2(d-2=10/3

We move all terms to the left:

-4(d+1)+2(d-2-(10/3)=0

We add all the numbers together, and all the variables

-4(d+1)+2(d-2-(+10/3)=0

We multiply parentheses

-4d+2(d-2-(+10/3)-4=0

We multiply all the terms by the denominator


-4d*3)-4+2(d-2-(+10=0

We add all the numbers together, and all the variables

-4d*3)-4+2(d=0

Wy multiply elements

-12d^2=0

a = -12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-12)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$d=\frac{-b}{2a}=\frac{0}{-24}=0$