5(1/2+2m)=1/2(8+20m)

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Solution for 5(1/2+2m)=1/2(8+20m) equation: 



5(1/2+2m)=1/2(8+20m)

We move all terms to the left:

5(1/2+2m)-(1/2(8+20m))=0



Domain of the equation: 2+2m)!=0

We move all terms containing m to the left, all other terms to the right

2m)!=-2

m!=-2/1

m!=-2

m∈R





Domain of the equation: 2(8+20m))!=0

m∈R



We add all the numbers together, and all the variables

5(+2m+1/2)-(1/2(20m+8))=0

We multiply parentheses

10m-(1/2(20m+8))+1/2*5=0

We calculate fractions


10m+()/(2(20m+8))*2*5)+(2m2/(2(20m+8))*2*5)=0



We calculate terms in parentheses: +()/(2(20m+8))*2*5)+(2m2/(2(20m+8))*2*5), so:

)/(2(20m+8))*2*5)+(2m2/(2(20m+8))*2*5

We can not solve this equation

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