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(4(x+3)/5=4x-12
We move all terms to the left:
(4(x+3)/5-(4x-12)=0
Domain of the equation: 5-(4x-12)!=0We multiply all the terms by the denominator
We move all terms containing x to the left, all other terms to the right
-(4x-12)!=-5
x∈R
(4(x+3)=0
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| −3x+3+5x=15 | | -(8,5+1,5y)+8y=-2 | | -7.8x=-17.16 | | 41b+20=11b | | 7y+4y-13+8=3y+19 | | 5c-1=-26 | | 3(a−5)−4=11. | | 52+(-x/3)+(-40)=x | | 16r=17 | | x-2+2x+5=180 | | F(x)=21x-105 | | 13t=8 | | a=-14+6 | | (x-24)3/4=27 | | p/3-(-5)=9 | | -2(-9-3n)=12 | | 9x+x-7x=39 | | -6+4(w-5)=-28 | | (2a+3)–(4a-8)=7 | | -r=-611 | | b/–3+–8=–12 | | w-43=79 | | -4n+n=0-6 | | -4-6g=-6g-4 | | 2x+4x-80=90 | | 9y²-36y=0 | | 5x-7-4=-7 | | 3-(-5x)=38 | | p+7.60=30.40 | | 4(0.5x-6)=x-0.25(12+8x) | | -792=6c | | 2.5x-3(x-4)=2.1(3+x) |