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5(1-x)+4(x-3)=(x-1)-(1-x)
We move all terms to the left:
5(1-x)+4(x-3)-((x-1)-(1-x))=0
We add all the numbers together, and all the variables
5(-1x+1)+4(x-3)-((x-1)-(-1x+1))=0
We multiply parentheses
-5x+4x-((x-1)-(-1x+1))+5-12=0
We calculate terms in parentheses: -((x-1)-(-1x+1)), so:We add all the numbers together, and all the variables
(x-1)-(-1x+1)
We get rid of parentheses
x+1x-1-1
We add all the numbers together, and all the variables
2x-2
Back to the equation:
-(2x-2)
-1x-(2x-2)-7=0
We get rid of parentheses
-1x-2x+2-7=0
We add all the numbers together, and all the variables
-3x-5=0
We move all terms containing x to the left, all other terms to the right
-3x=5
x=5/-3
x=-1+2/3
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