2(v-5)-1=-6(-4v+3)-8v

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Solution for 2(v-5)-1=-6(-4v+3)-8v equation: 



2(v-5)-1=-6(-4v+3)-8v

We move all terms to the left:

2(v-5)-1-(-6(-4v+3)-8v)=0

We multiply parentheses

2v-(-6(-4v+3)-8v)-10-1=0



We calculate terms in parentheses: -(-6(-4v+3)-8v), so:

-6(-4v+3)-8v

We add all the numbers together, and all the variables

-8v-6(-4v+3)

We multiply parentheses

-8v+24v-18

We add all the numbers together, and all the variables

16v-18

Back to the equation:

-(16v-18)



We add all the numbers together, and all the variables

2v-(16v-18)-11=0

We get rid of parentheses

2v-16v+18-11=0

We add all the numbers together, and all the variables

-14v+7=0

We move all terms containing v to the left, all other terms to the right

-14v=-7

v=-7/-14

v=1/2

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