5(1+x)=8x-2(x-2)

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Solution for 5(1+x)=8x-2(x-2) equation: 



5(1+x)=8x-2(x-2)

We move all terms to the left:

5(1+x)-(8x-2(x-2))=0

We add all the numbers together, and all the variables

5(x+1)-(8x-2(x-2))=0

We multiply parentheses

5x-(8x-2(x-2))+5=0



We calculate terms in parentheses: -(8x-2(x-2)), so:

8x-2(x-2)

We multiply parentheses

8x-2x+4

We add all the numbers together, and all the variables

6x+4

Back to the equation:

-(6x+4)



We get rid of parentheses

5x-6x-4+5=0

We add all the numbers together, and all the variables

-1x+1=0

We move all terms containing x to the left, all other terms to the right

-x=-1

x=-1/-1

x=1

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