5(1+c)=4(c-5)

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Solution for 5(1+c)=4(c-5) equation:


Simplifying
5(1 + c) = 4(c + -5)
(1 * 5 + c * 5) = 4(c + -5)
(5 + 5c) = 4(c + -5)

Reorder the terms:
5 + 5c = 4(-5 + c)
5 + 5c = (-5 * 4 + c * 4)
5 + 5c = (-20 + 4c)

Solving
5 + 5c = -20 + 4c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4c' to each side of the equation.
5 + 5c + -4c = -20 + 4c + -4c

Combine like terms: 5c + -4c = 1c
5 + 1c = -20 + 4c + -4c

Combine like terms: 4c + -4c = 0
5 + 1c = -20 + 0
5 + 1c = -20

Add '-5' to each side of the equation.
5 + -5 + 1c = -20 + -5

Combine like terms: 5 + -5 = 0
0 + 1c = -20 + -5
1c = -20 + -5

Combine like terms: -20 + -5 = -25
1c = -25

Divide each side by '1'.
c = -25

Simplifying
c = -25

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