-4(5a-5)=2(3-10a)+14

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Solution for -4(5a-5)=2(3-10a)+14 equation: 


Simplifying
-4(5a + -5) = 2(3 + -10a) + 14

Reorder the terms:
-4(-5 + 5a) = 2(3 + -10a) + 14
(-5 * -4 + 5a * -4) = 2(3 + -10a) + 14
(20 + -20a) = 2(3 + -10a) + 14
20 + -20a = (3 * 2 + -10a * 2) + 14
20 + -20a = (6 + -20a) + 14

Reorder the terms:
20 + -20a = 6 + 14 + -20a

Combine like terms: 6 + 14 = 20
20 + -20a = 20 + -20a

Add '-20' to each side of the equation.
20 + -20 + -20a = 20 + -20 + -20a

Combine like terms: 20 + -20 = 0
0 + -20a = 20 + -20 + -20a
-20a = 20 + -20 + -20a

Combine like terms: 20 + -20 = 0
-20a = 0 + -20a
-20a = -20a

Add '20a' to each side of the equation.
-20a + 20a = -20a + 20a

Combine like terms: -20a + 20a = 0
0 = -20a + 20a

Combine like terms: -20a + 20a = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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