5(1+2m)=1/2+20m)

Solution for 5(1+2m)=1/2+20m) equation:

5(1+2m)=1/2+20m)

We move all terms to the left:

5(1+2m)-(1/2+20m))=0


Domain of the equation: 2+20m))!=0

We move all terms containing m to the left, all other terms to the right

20m))!=-2

m!=-2/1

m!=-2

m∈R


We add all the numbers together, and all the variables

5(2m+1)-(+20m+1/2))=0

We multiply parentheses

10m-(+20m+1/2))+5=0

We multiply all the terms by the denominator


10m*2))+5-(+20m+1=0

Wy multiply elements

20m^2=0

a = 20; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·20·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{0}{40}=0$