-(1+3x)+3=7(3+3x)-5x

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Solution for -(1+3x)+3=7(3+3x)-5x equation: 



-(1+3x)+3=7(3+3x)-5x

We move all terms to the left:

-(1+3x)+3-(7(3+3x)-5x)=0

We add all the numbers together, and all the variables

-(3x+1)-(7(3x+3)-5x)+3=0

We get rid of parentheses

-3x-(7(3x+3)-5x)-1+3=0



We calculate terms in parentheses: -(7(3x+3)-5x), so:

7(3x+3)-5x

We add all the numbers together, and all the variables

-5x+7(3x+3)

We multiply parentheses

-5x+21x+21

We add all the numbers together, and all the variables

16x+21

Back to the equation:

-(16x+21)



We add all the numbers together, and all the variables

-3x-(16x+21)+2=0

We get rid of parentheses

-3x-16x-21+2=0

We add all the numbers together, and all the variables

-19x-19=0

We move all terms containing x to the left, all other terms to the right

-19x=19

x=19/-19

x=-1

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