5(-h+2)=4h+5-(-2h+4)

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Solution for 5(-h+2)=4h+5-(-2h+4) equation: 



5(-h+2)=4h+5-(-2h+4)

We move all terms to the left:

5(-h+2)-(4h+5-(-2h+4))=0

We add all the numbers together, and all the variables

5(-1h+2)-(4h+5-(-2h+4))=0

We multiply parentheses

-5h-(4h+5-(-2h+4))+10=0



We calculate terms in parentheses: -(4h+5-(-2h+4)), so:

4h+5-(-2h+4)

determiningTheFunctionDomain
4h-(-2h+4)+5

We get rid of parentheses

4h+2h-4+5

We add all the numbers together, and all the variables

6h+1

Back to the equation:

-(6h+1)



We get rid of parentheses

-5h-6h-1+10=0

We add all the numbers together, and all the variables

-11h+9=0

We move all terms containing h to the left, all other terms to the right

-11h=-9

h=-9/-11

h=9/11

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