5(-3x-2)-(x-3)=4(x+5)+13

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Solution for 5(-3x-2)-(x-3)=4(x+5)+13 equation: 



5(-3x-2)-(x-3)=4(x+5)+13

We move all terms to the left:

5(-3x-2)-(x-3)-(4(x+5)+13)=0

We multiply parentheses

-15x-(x-3)-(4(x+5)+13)-10=0

We get rid of parentheses

-15x-x-(4(x+5)+13)+3-10=0



We calculate terms in parentheses: -(4(x+5)+13), so:

4(x+5)+13

We multiply parentheses

4x+20+13

We add all the numbers together, and all the variables

4x+33

Back to the equation:

-(4x+33)



We add all the numbers together, and all the variables

-16x-(4x+33)-7=0

We get rid of parentheses

-16x-4x-33-7=0

We add all the numbers together, and all the variables

-20x-40=0

We move all terms containing x to the left, all other terms to the right

-20x=40

x=40/-20

x=-2

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