((4x+2)/9)-((2x+1)/2)=1/6

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Solution for ((4x+2)/9)-((2x+1)/2)=1/6 equation: 



((4x+2)/9)-((2x+1)/2)=1/6

We move all terms to the left:

((4x+2)/9)-((2x+1)/2)-(1/6)=0

We add all the numbers together, and all the variables

((4x+2)/9)-((2x+1)/2)-(+1/6)=0

We get rid of parentheses

((4x+2)/9)-((2x+1)/2)-1/6=0

We calculate fractions


(((4x+2)*2)*6)/()+(-((2x+1)*9)*6)/()+()/()=0



We calculate terms in parentheses: +(((4x+2)*2)*6)/(), so:

((4x+2)*2)*6)/(

We multiply all the terms by the denominator


((4x+2)*2)*6)



We calculate terms in parentheses: +((4x+2)*2)*6), so:

(4x+2)*2)*6

We multiply parentheses

24x+

We add all the numbers together, and all the variables

24x

Back to the equation:

+(24x)



Back to the equation:

+(24x)





We calculate terms in parentheses: +(-((2x+1)*9)*6)/(), so:

-((2x+1)*9)*6)/(

We multiply all the terms by the denominator


-((2x+1)*9)*6)



We calculate terms in parentheses: -((2x+1)*9)*6), so:

(2x+1)*9)*6

We multiply parentheses

12x+

We add all the numbers together, and all the variables

12x

Back to the equation:

-(12x)



Back to the equation:

+(-12x)



We add all the numbers together, and all the variables

24x+(-12x)+1=0

We get rid of parentheses

24x-12x+1=0

We add all the numbers together, and all the variables

12x+1=0

We move all terms containing x to the left, all other terms to the right

12x=-1

x=-1/12

x=-1/12

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