5(-3x+2)-2(4x+1)=3(4x-1)-8

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Solution for 5(-3x+2)-2(4x+1)=3(4x-1)-8 equation: 



5(-3x+2)-2(4x+1)=3(4x-1)-8

We move all terms to the left:

5(-3x+2)-2(4x+1)-(3(4x-1)-8)=0

We multiply parentheses

-15x-8x-(3(4x-1)-8)+10-2=0



We calculate terms in parentheses: -(3(4x-1)-8), so:

3(4x-1)-8

We multiply parentheses

12x-3-8

We add all the numbers together, and all the variables

12x-11

Back to the equation:

-(12x-11)



We add all the numbers together, and all the variables

-23x-(12x-11)+8=0

We get rid of parentheses

-23x-12x+11+8=0

We add all the numbers together, and all the variables

-35x+19=0

We move all terms containing x to the left, all other terms to the right

-35x=-19

x=-19/-35

x=19/35

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