2-2/3(c-6)=12

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Solution for 2-2/3(c-6)=12 equation: 



2-2/3(c-6)=12

We move all terms to the left:

2-2/3(c-6)-(12)=0



Domain of the equation: 3(c-6)!=0

c∈R



We add all the numbers together, and all the variables

-2/3(c-6)-10=0

We multiply all the terms by the denominator


-10*3(c-6)-2=0

Wy multiply elements

-30c(c-2=0

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