5(-20z+3)-13=20(-5z+2)-35

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Solution for 5(-20z+3)-13=20(-5z+2)-35 equation: 



5(-20z+3)-13=20(-5z+2)-35

We move all terms to the left:

5(-20z+3)-13-(20(-5z+2)-35)=0

We multiply parentheses

-100z-(20(-5z+2)-35)+15-13=0



We calculate terms in parentheses: -(20(-5z+2)-35), so:

20(-5z+2)-35

We multiply parentheses

-100z+40-35

We add all the numbers together, and all the variables

-100z+5

Back to the equation:

-(-100z+5)



We add all the numbers together, and all the variables

-100z-(-100z+5)+2=0

We get rid of parentheses

-100z+100z-5+2=0

We add all the numbers together, and all the variables

-3!=0

There is no solution for this equation

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