14+14(y-5)=2(3-y)

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Solution for 14+14(y-5)=2(3-y) equation: 



14+14(y-5)=2(3-y)

We move all terms to the left:

14+14(y-5)-(2(3-y))=0

We add all the numbers together, and all the variables

14(y-5)-(2(-1y+3))+14=0

We multiply parentheses

14y-(2(-1y+3))-70+14=0



We calculate terms in parentheses: -(2(-1y+3)), so:

2(-1y+3)

We multiply parentheses

-2y+6

Back to the equation:

-(-2y+6)



We add all the numbers together, and all the variables

14y-(-2y+6)-56=0

We get rid of parentheses

14y+2y-6-56=0

We add all the numbers together, and all the variables

16y-62=0

We move all terms containing y to the left, all other terms to the right

16y=62

y=62/16

y=3+7/8

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