4z-6=6(z+2)=8

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Solution for 4z-6=6(z+2)=8 equation: 



4z-6=6(z+2)=8

We move all terms to the left:

4z-6-(6(z+2))=0



We calculate terms in parentheses: -(6(z+2)), so:

6(z+2)

We multiply parentheses

6z+12

Back to the equation:

-(6z+12)



We get rid of parentheses

4z-6z-12-6=0

We add all the numbers together, and all the variables

-2z-18=0

We move all terms containing z to the left, all other terms to the right

-2z=18

z=18/-2

z=-9

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