4n-9=2(5+n2)

Solution for 4n-9=2(5+n2) equation:

4n-9=2(5+n2)

We move all terms to the left:

4n-9-(2(5+n2))=0

We add all the numbers together, and all the variables

-(2(+n^2+5))+4n-9=0


We calculate terms in parentheses: -(2(+n^2+5)), so:

2(+n^2+5)

We multiply parentheses

2n^2+10

Back to the equation:

-(2n^2+10)


We add all the numbers together, and all the variables

4n-(2n^2+10)-9=0

We get rid of parentheses

-2n^2+4n-10-9=0

We add all the numbers together, and all the variables

-2n^2+4n-19=0

a = -2; b = 4; c = -19;
Δ = b2-4ac
Δ = 42-4·(-2)·(-19)
Δ = -136
Delta is less than zero, so there is no solution for the equation