4z-1=2(z+3)

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Solution for 4z-1=2(z+3) equation: 



4z-1=2(z+3)

We move all terms to the left:

4z-1-(2(z+3))=0



We calculate terms in parentheses: -(2(z+3)), so:

2(z+3)

We multiply parentheses

2z+6

Back to the equation:

-(2z+6)



We get rid of parentheses

4z-2z-6-1=0

We add all the numbers together, and all the variables

2z-7=0

We move all terms containing z to the left, all other terms to the right

2z=7

z=7/2

z=3+1/2

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