3(4x+-5)=33

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Solution for 3(4x+-5)=33 equation: 



3(4x+-5)=33

We move all terms to the left:

3(4x+-5)-(33)=0

We add all the numbers together, and all the variables

3(4x-5)-33=0

We multiply parentheses

12x-15-33=0

We add all the numbers together, and all the variables

12x-48=0

We move all terms containing x to the left, all other terms to the right

12x=48

x=48/12

x=4

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